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c語(yǔ)言分段函數(shù)1 c語(yǔ)言分段函數(shù)怎么寫(xiě)

C語(yǔ)言計(jì)算分段函數(shù)

1. 代碼如下,3)需要實(shí)際運(yùn)行時(shí)輸入測(cè)試

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int main(void)

{

double x, y, f;

printf("Please input 2 double number in the form of x y:\n");

scanf("%lf%lf", x, y);

if(x=0 y0)

f = 2*x*x + 3*x +1/(x+y);

else if(x=0 y=0)

f = 2*x*x + 3*x +1/(1+y*y);

else

f = 3*sin(x+y)/(2*x*x) + 3*x + 1;

printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);

return 0;

}

2.代碼如下

#include stdio.h

#includemath.h

int main(void)

{

double x, y, f;

printf("Please input 2 double number in the form of x y:\n");

scanf("%lf%lf", x, y);

if(x=0)

{

if(y0)

f = 2*x*x + 3*x +1/(x+y);

else

f = 2*x*x + 3*x +1/(1+y*y);

}

else

f = 3*sin(x+y)/(2*x*x) + 3*x + 1;

printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);

return 0;

}

3.代碼如下

#include stdio.h

int main(void)

{

int score = 0;

printf("Please input a score between 0-100:\n");

scanf("%d", score);

if(score0 || score100)

printf("Wrong input of score!\n");

else if(score=90 score=100)

printf("A\n");

else if(score=80 score=89)

printf("B\n");

else if(score=70 score=79)

printf("C\n");

else if(score=60 score=69)

printf("D\n");

else

printf("E\n");

return 0;

}

C語(yǔ)言編寫(xiě)分段函數(shù)

#includestdio.h

int?main()

{

int?x,y;

scanf("%d",x);

if(x-10)

y=0;

else?if(x100)?y=5*x+1;

else

??y?=?5*x?+?1;?//這個(gè)表達(dá)式的值是什么啊

printf("%d\n",y);

return?0;

}

C語(yǔ)言分段函數(shù)

簡(jiǎn)單寫(xiě)一下主函數(shù)

int x,y;

printf("x=");

scanf("%d",x);

if(x==0){

y=-1;

printf("y=%d",y);}

else if(x0){

y=x;

printf("y=%d",y);}

else if(x0x10){

y=x+1;

printf("y=%d",y);}

else{

printf("****不在范圍內(nèi)");}

return 0;

c語(yǔ)言分段函數(shù)

寫(xiě)法1

if (x-5 x0) y = x;

if (x == 0) y=x-1;

if (x0 x10) y = x+1;

寫(xiě)法2

if (x-5 x10)

{

y=x; //在這個(gè)范圍,不論怎樣,先把y賦值為x

if (x=0) //在這個(gè)范圍,需要對(duì)y值做修改

{

y = y-1; //先把y-1再說(shuō),對(duì)應(yīng)x=0的情況,如果x!=0,那么我們?cè)俅涡薷?/p>

if(x0)

y = y+2; //剛剛y-1了,所以需要+2

}

}

寫(xiě)法3,終于是正常點(diǎn)的做法了

if (x-5 x0) y=x;

else

{

if (x10)

{

if (x==0) y=x-1;

else y=x+1;

}

}

寫(xiě)法4

switch(x)

{

case 0:

y=x-1;

break;

case -4;

case -3;

case -2;

case -1;

y=x;

break;

case 1;

case 2;

case 3;

case 4;

case 5;

case 6;

case 7;

case 8;

case 9;

y=x+1;

break;

}

怎么用c語(yǔ)言編程一個(gè)分段函數(shù)?

#include

int?main()

{

int?x,y;

scanf("%d",x);

if(0xx10)?y=3*x+2;

else

{if(x=0)?y=0;

else

{if?(x0)?y=x*x;

else?printf("go?die\n");

}

}

printf("%d",y);

return?0;

}該程序的分段函數(shù)如下:

f(x)=3x+2? (0x10)

f(x)=1???????? (x=0)

f(x)?=?x*x??? (x0)

#include stdio.h

#include math.h

void main()

{

float x;

double y;

printf("Please input the value of x:");

scanf("%f",x);

if(x=-10x=4)

{

y=fabs(x-2);

printf("y=%.2f\n",y);

}

else if(x=5x=7)

{

y=x+10;

printf("y=%.2f\n",y);

}

else if(x=8x=12)

{

y=pow(x,4);

printf("y=%.2f\n",y);

}

else

printf("No answer\n");

}

如何用C語(yǔ)言運(yùn)行一個(gè)分段函數(shù)呀?

#include stdio.h

#include math.h

int main()

{

float x,y;

printf("please input x:");

scanf("%f",x);

if(x0 x!=-3)

?y = pow(x,2)+x-6;

else if(x=0 x10 x!=2 x!=3)

?y = pow(x,2)-5*x+6;

else

?y = pow(x,2)-x-1;

printf("y=%f\n",y);

return 0;

}

文章名稱(chēng):c語(yǔ)言分段函數(shù)1 c語(yǔ)言分段函數(shù)怎么寫(xiě)
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