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java多線程編程題代碼 java多線程編程題代碼怎么寫

java多線程編程代碼如下,輸出結(jié)果如下:

首先,你同步的是具體的某個(gè)Test實(shí)例, 對(duì)于那個(gè)實(shí)例來說,實(shí)際上只有一個(gè)線程訪問了那個(gè)代碼塊,但是sum和other卻是多個(gè)線程同時(shí)去進(jìn)行訪問,實(shí)際上這是不安全的,如果你想實(shí)現(xiàn)每次都輸出10000的效果,那么正確的應(yīng)該是在Test.class上加鎖,而不是獲取Test實(shí)例的鎖,修改后的代碼如下:

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public?class?Test?extends?Thread?{

public?static?int?sum?=?10000;

public?static?int?other?=?0;

public?void?getMoney()?{

synchronized?(Test.class)?{

System.out.println(Thread.currentThread().getName()?+?"?開始執(zhí)行");

sum?=?sum?-?100;

System.out.println("sum-100");

other?=?other?+?100;

System.out.println("other+100");

System.out.println(sum?+?other);

System.out.println(Thread.currentThread().getName()?+?"?執(zhí)行完成");

}

}

public?void?run()?{

getMoney();

}

public?static?void?main(String[]?agrs)?{

Thread?t[]?=?new?Thread[10];

for?(int?i?=?0;?i?=?9;?i++)?{

t[i]?=?new?Test();

t[i].start();

}

}

}

// 上面代碼能得到你的結(jié)果

java編程題目:實(shí)現(xiàn)多線程累加,求代碼

照著下面的例子改一下:

/**

* 實(shí)現(xiàn)Runnable接口的類

*

* @author leizhimin 2008-9-13 18:12:10

*/

publicclass DoSomethingimplements Runnable {

private String name;

public DoSomething(String name) {

this.name = name;

}

publicvoid run() {

for (int i = 0; i 5; i++) {

for (long k = 0; k 100000000; k++) ;

System.out.println(name + ": " + i);

}

}

}

/**

* 測(cè)試Runnable類實(shí)現(xiàn)的多線程程序

*

* @author leizhimin 2008-9-13 18:15:02

*/

publicclass TestRunnable {

publicstaticvoid main(String[] args) {

DoSomething ds1 = new DoSomething("阿三");

DoSomething ds2 = new DoSomething("李四");

Thread t1 = new Thread(ds1);

Thread t2 = new Thread(ds2);

t1.start();

t2.start();

}

}

執(zhí)行結(jié)果:

李四: 0

阿三: 0

李四: 1

阿三: 1

李四: 2

李四: 3

阿三: 2

李四: 4

阿三: 3

阿三: 4

Process finished with exit code 0

2、擴(kuò)展Thread類實(shí)現(xiàn)的多線程例子

/**

* 測(cè)試擴(kuò)展Thread類實(shí)現(xiàn)的多線程程序

*

* @author leizhimin 2008-9-13 18:22:13

*/

publicclass TestThreadextends Thread{

public TestThread(String name) {

super(name);

}

publicvoid run() {

for(int i = 0;i5;i++){

for(long k= 0; k 100000000;k++);

System.out.println(this.getName()+" :"+i);

}

}

publicstaticvoid main(String[] args) {

Thread t1 = new TestThread("阿三");

Thread t2 = new TestThread("李四");

t1.start();

t2.start();

}

}

執(zhí)行結(jié)果:

阿三 :0

李四 :0

阿三 :1

李四 :1

阿三 :2

李四 :2

阿三 :3

阿三 :4

李四 :3

李四 :4

Process finished with exit code 0

java多線程編程題 跪求求解

package?com.zhidao20161220;

public?class?Main?{

private?static?int?count=0;

public?static?void?main(String[]?args)?{

//?TODO?Auto-generated?method?stub

for(int?i=0;i10;i++)

{

String?name?=?"人員"+(i+1);

ManThread?manThread?=?new?ManThread(name);

manThread.start();

}

}

public?static?synchronized?void?go(String?name)

{

count++;

System.out.println("線程"+Thread.currentThread().getName()+"執(zhí)行,"+name+"正在通過山洞");

try?{

if(count=10)

{

System.out.println("全員通過程序結(jié)束");

}

Thread.sleep(5000);

}?catch?(InterruptedException?e)?{

//?TODO?Auto-generated?catch?block

e.printStackTrace();

}

}

}

package?com.zhidao20161220;

public?class?ManThread?extends?Thread?{

private?String?name;

public?ManThread(String?name)

{

this.name?=?name;

}

public?void?run()?{

Main.go(name);

}

}

JAVA多線程 編程題兩個(gè)案例,不會(huì)寫,求大神寫出代碼,萬分感謝,多線程還沒學(xué)。

/*

class A extends Thread

{

public void run()

{

try

{

Thread.sleep(1000);

}catch(Exception e)

{

System.out.println("A ERROR!");

}

System.out.println("AAAA");

}

}

class B extends Thread

{

public void run()

{

try

{

Thread.sleep(2000);

}catch(Exception e)

{

System.out.println("B ERROR!");

}

System.out.println("BBBB");

}

}

class C extends Thread

{

public void run()

{

try

{

Thread.sleep(3000);

}catch(Exception e)

{

System.out.println("C ERROR!");

}

System.out.println("CCCC");

}

}

public class Test_1

{

public static void main(String[] args)

{

A a = new A();

B b = new B();

C c = new C();

a.start();

b.start();

c.start();

}

}*/

public class Test_1

{

public static void main(String[] args)

{

A a = new A();

B b = new B();

C c = new C();

Thread ta = new Thread(a);

Thread tb = new Thread(b);

Thread tc = new Thread(c);

ta.start();

tb.start();

tc.start();

}

}

class A implements Runnable

{

public void run()

{

try

{

Thread.sleep(1000);

}catch(Exception e)

{

System.out.println("A ERROR!");

}

System.out.println("AAAA");

}

}

class B implements Runnable

{

public void run()

{

try

{

Thread.sleep(2000);

}catch(Exception e)

{

System.out.println("B ERROR!");

}

System.out.println("BBBB");

}

}

class C implements Runnable

{

public void run()

{

try

{

Thread.sleep(3000);

}catch(Exception e)

{

System.out.println("C ERROR!");

}

System.out.println("CCCC");

}

}

案例一的兩種方法已經(jīng)寫好;現(xiàn)在有事,晚上再把案例二代碼寫一下,應(yīng)該沒關(guān)系吧!

抱歉,是一個(gè)線程類,我看錯(cuò)了,晚上重發(fā)一下代碼!

Java關(guān)于io和多線程的編程題,求代碼

package?know;

import?java.io.BufferedReader;

import?java.io.FileInputStream;

import?java.io.IOException;

import?java.io.InputStreamReader;

import?java.util.HashMap;

import?java.util.Map;

import?java.util.Scanner;

public?class?T20?{

public?static?void?main(String[]?args)?throws?IOException?{

Scanner?s=new?Scanner(System.in);

String?username=null;

String?password=null;

System.out.println("輸入用戶名:");

while(true){

if(username==null){

username=s.next();

System.out.println("輸入密碼:");

}else{

password=s.next();

}

if(password!=null){

s.close();

break;

}

}

BufferedReader?br=null;

MapString,?String?map=new?HashMapString,?String();

try{

br=new?BufferedReader(new?InputStreamReader(new?FileInputStream("d:/test.txt")));

String?temp=null;???

while((temp=br.readLine())!=null){

String[]?ss=temp.split("=");

map.put(ss[0],?ss[1]);

}

}catch(IOException?e){

throw?e;

}finally{

if(br!=null)

br.close();

}

String?u=map.get("userName");

String?p=map.get("password");

if(u.equals(username)p.equals(password)){

System.out.println("登錄成功");

}else{

System.out.println("用戶名或密碼錯(cuò)誤");

}

}

}

package?know;

public?class?T21?{

public?static?void?main(String[]?args)?throws?InterruptedException?{

String[]?persons=new?String[]{"甲","乙","丙","丁","午","己","庚","辛","壬","癸"};

for(int?i=0;ipersons.length;i++){

System.out.println(persons[i]+"正在過山洞");

Thread.sleep(5000);

}

}

}

最后一個(gè)百度搜一個(gè)就行了,肯定比我畫的好

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