關(guān)聯(lián)查詢即可實現(xiàn),表1關(guān)聯(lián)表2,條件就是你如何從表1找到表2,關(guān)聯(lián)后可以同時獲取兩個表的所有字段,就可以過濾字段,指定顯示的字段,格式參考:select a.字段,b.genger from 表1 a join 表2 b on a.條件字段=b.條件字段。

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update table set name='f' where id = 1;
update table set name='f' where id 1 id 5;
什么數(shù)據(jù)庫?\x0d\x0a如果是 Oracle 或者 SQL Server 的話。 可以\x0d\x0a\x0d\x0aSELECT\x0d\x0a *\x0d\x0aFROM\x0d\x0a(\x0d\x0a SELECT ROW_NUMBER() OVER( ORDER BY 排序的字段 ) AS 序號\x0d\x0a 表.*\x0d\x0a FROM\x0d\x0a 表\x0d\x0a) tmp\x0d\x0aWHERE\x0d\x0a tmp.序號 = 12345\x0d\x0a\x0d\x0a如果是 MySQL 的話, 直接\x0d\x0aSELECT * FROM 表 LIMIT 12344, 1\x0d\x0a注:\x0d\x0aLIMIT 接受一個或兩個數(shù)字參數(shù)。\x0d\x0a參數(shù)必須是一個整數(shù)常量。\x0d\x0a如果給定兩個參數(shù),第一個參數(shù)指定第一個返回記錄行的偏移量,\x0d\x0a第二個參數(shù)指定返回記錄行的最大數(shù)目。\x0d\x0a初始記錄行的偏移量是 0(而不是 1)
select *
from 表名
limit 10, 11
注:第10條到第20條共計11條記錄
mysql如何指定查詢一張表的查詢結(jié)果,如最后5行記錄和最前5行記錄
mysql如何指定查詢一張表的查詢結(jié)果,如最后5行記錄和最前5行記錄
我們以student表為例,里面有三個字段:id,name,age,其中id為主健,為自增,里面共有10條記錄,如下所示。
mysql select * from student;
+----+------+------+
| id | name | age |
+----+------+------+
| 1 | li | 11 |
| 2 | zh | 12 |
| 3 | chou | 13 |
| 4 | he | 14 |
| 5 | lin | 15 |
| 6 | ll | 16 |
| 7 | chen | 17 |
| 8 | yu | 18 |
| 9 | wu | 19 |
| 10 | xie | 20 |
+----+------+------+
10 rows in set (0.00 sec)
1、查詢第一行記錄
select * from student limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 1 | li | 11 |
+----+------+------+
1 row in set (0.00 sec)
2、查詢最后一行記錄
select * from student order by id desc limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 10 | xie | 20 |
+----+------+------+
1 row in set (0.00 sec)
3、查詢前n行記錄,如前5行
select * from student limit 5;
select * from student limit 0,5;
select * from student order by id asc limit 5;
上面三條語句的結(jié)果都是一樣的,如下:
+----+------+------+
| id | name | age |
+----+------+------+
| 1 | li | 11 |
| 2 | zh | 12 |
| 3 | chou | 13 |
| 4 | he | 14 |
| 5 | lin | 15 |
+----+------+------+
5 rows in set (0.00 sec)
4、查詢后n行記錄,如后5條,注意結(jié)果為倒序排序,因為用了desc
select * from student order by id desc limit 5;
+----+------+------+
| id | name | age |
+----+------+------+
| 10 | xie | 20 |
| 9 | wu | 19 |
| 8 | yu | 18 |
| 7 | chen | 17 |
| 6 | ll | 16 |
+----+------+------+
5 rows in set (0.00 sec)
5、查詢第m行到第n行記錄,注意表中的記錄下標是從0開始的,就像數(shù)組一樣
select * from student limit m,n; 返回m+1到m+n行記錄,m代表開始的下標,n代表查找的結(jié)果數(shù),將返回n行結(jié)果
select * from student limit 2,8; 返回3到10行記錄
+----+------+------+
| id | name | age |
+----+------+------+
| 3 | chou | 13 |
| 4 | he | 14 |
| 5 | lin | 15 |
| 6 | ll | 16 |
| 7 | chen | 17 |
| 8 | yu | 18 |
| 9 | wu | 19 |
| 10 | xie | 20 |
+----+------+------+
8 rows in set (0.00 sec)
select * from student limit 3,1; 返回第4行
+----+------+------+
| id | name | age |
+----+------+------+
| 4 | he | 14 |
+----+------+------+
1 row in set (0.00 sec)
6、查詢一條記錄($id)的下一條記錄
select * from student where id$id order by id asc limit 1;
如$id=4時將返回第5條記錄
select * from student where id4 order by id asc limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 5 | lin | 15 |
+----+------+------+
1 row in set (0.00 sec)
7、查詢一條記錄($id)的上一條記錄
select * from student where id$id order by id desc limit 1;
如$id=4時將返回第3條記錄
select * from student where id4 order by id desc limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 3 | chou | 13 |
+----+------+------+
1 row in set (0.00 sec)
1、創(chuàng)建測試表,
create table test_limit(id int ,value varchar(100));
2、插入測試數(shù)據(jù),共6條記錄;
insert into test_limit values (1,'v1');
insert into test_limit values (2,'v2');
insert into test_limit values (3,'v3');
insert into test_limit values (4,'v4');
insert into test_limit values (5,'v5');
insert into test_limit values (6,'v6');
3、查詢表中全量數(shù)據(jù),可以發(fā)現(xiàn)共6條數(shù)據(jù),select * from test_limit t;
4、編寫語句,指定查詢3條數(shù)據(jù);
select * from test_limit limit 3;
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