select pkdz.id ,zsmx.id as zsmxid,pzty.typh_q, pzty.typh_z, pzty.szsk, skxx.swjgid,zsmx.je from pz_pztyjl pzty
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join pz_pkdzjl pkdz on (pzty.pkdzjl_id = pkdz.id )
join sk_hd_zsmx zsmx on ( pkdz.id = zsmx.tyjks_id )
join sk_zt_skxx skxx on (zsmx.skxx_id = skxx.id)
order by pkdz.id asc, zsmx.id asc
Oracle按不同時(shí)間分組統(tǒng)計(jì)的sql
如下表table1:
日期(exportDate)
數(shù)量(amount)
--------------
-----------
14-2月
-08
20
10-3月
-08
2
14-4月
-08
6
14-6月
-08
75
24-10月-09
23
14-11月-09
45
04-8月
-10
5
04-9月
-10
44
04-10月-10
88
注意:為了顯示更直觀,如下查詢已皆按相應(yīng)分組排序
1.按年份分組
select
to_char(exportDate,'yyyy'),sum(amount)
from
table1
group
by
to_char(exportDate,'yyyy');
年份
數(shù)量
-----------------------------
2009
68
2010
137
2008
103
2.按月份分組
select
to_char(exportDate,'yyyy-mm'),sum(amount)
from
table1
group
by
to_char(exportDate,'yyyy-mm')
order
by
to_char(exportDate,'yyyy-mm');
月份
數(shù)量
-----------------------------
2008-02
20
2008-03
2
2008-04
6
2008-06
75
2009-10
23
2009-11
45
2010-08
5
2010-09
44
2010-10
88
3.按季度分組
select
to_char(exportDate,'yyyy-Q'),sum(amount)
from
table1
group
by
to_char(exportDate,'yyyy-Q')
order
by
to_char(exportDate,'yyyy-Q');
季度
數(shù)量
------------------------------
2008-1
22
2008-2
81
2009-4
68
2010-3
49
2010-4
88
4.按周分組
select
to_char(exportDate,'yyyy-IW'),sum(amount)
from
table1
group
by
to_char(exportDate,'yyyy-IW')
order
by
to_char(exportDate,'yyyy-IW');
周
數(shù)量
------------------------------
2008-07
20
2008-11
2
2008-16
6
2008-24
75
2009-43
23
2009-46
45
2010-31
5
2010-35
44
2010-40
88
PS:Oracle按時(shí)間段分組統(tǒng)計(jì)
想要按時(shí)間段分組查詢,首先要了解level,connect
by,oracle時(shí)間的加減.
關(guān)于level這里不多說(shuō),我只寫(xiě)出一個(gè)查詢語(yǔ)句:
----level
是一個(gè)偽例
select
level
from
dual
connect
by
level
=10
---結(jié)果:
1
2
3
4
5
6
7
8
9
10
oracle時(shí)間的加減看看試一下以下sql語(yǔ)句就會(huì)知道:
select
sysdate
-1
from
dual
----結(jié)果減一天,也就24小時(shí)
select
sysdate-(1/2)
from
dual
-----結(jié)果減去半天,也就12小時(shí)
select
sysdate-(1/24)
from
dual
-----結(jié)果減去1
小時(shí)
select
sysdate-((1/24)/12)
from
dual
----結(jié)果減去5分鐘
select
sydate-(level-1)
from
dual
connect
by
level=10
---結(jié)果是10間隔1天的時(shí)間
下面是本次例子:
select
dt,
count(satisfy_degree)
as
num
from
T_DEMO
i
,
(select
sysdate
-
(level-1)
*
2
dt
from
dual
connect
by
level
=
10)
d
where
i.satisfy_degree='satisfy_1'
and
i.insert_timedt
and
i.insert_time
d.dt-2
group
by
d.dt
例子中的sysdate
-
(level-1)
*
2得到的是一個(gè)間隔是2天的時(shí)間
group
by
d.dt
也就是兩天的時(shí)間間隔分組查詢
自己實(shí)現(xiàn)例子:
create
table
A_HY_LOCATE1
(
MOBILE_NO
VARCHAR2(32),
LOCATE_TYPE
NUMBER(4),
AREA_NO
VARCHAR2(32),
CREATED_TIME
DATE,
AREA_NAME
VARCHAR2(512),
);
select
(sysdate-13)-(level-1)/4
from
dual
connect
by
level=34
--從第一條時(shí)間記錄開(kāi)始(sysdate-13)為表中的最早的日期,“34”出現(xiàn)的分組數(shù)(一天按每六個(gè)小時(shí)分組
就應(yīng)該為4)
一下是按照每6個(gè)小時(shí)分組
select
mobile_no,area_name,max(created_time
),dt,
count(*)
as
num
from
a_hy_locate1
i
,
(select
(sysdate-13)-(level-1)/4
dt
from
dual
connect
by
level
=
34)
d
where
i.locate_type
=
1
and
i.created_timedt
and
i.created_time
d.dt-1/4
group
by
mobile_no,area_name,d.dt
另外一個(gè)方法:
--按六小時(shí)分組
select
trunc(to_number(to_char(created_time,
'hh24'))
/
6),count(*)
from
t_test
where
created_time
trunc(sysdate
-
40)
group
by
trunc(to_number(to_char(created_time,
'hh24'))
/
6)
--按12小時(shí)分組
select
trunc(to_number(to_char(created_time,
'hh24'))
/
6),count(*)
from
t_test
where
created_time
trunc(sysdate
-
40)
group
by
trunc(to_number(to_char(created_time,
'hh24'))
/
6)
info表的use字段會(huì)有重復(fù)的嗎比如userA@userA,這樣算一個(gè)還是2個(gè)?
如果沒(méi)有重復(fù)或只算一個(gè)的話可以這么統(tǒng)計(jì),不過(guò)效率是慢點(diǎn)....
select
userID,(select
count(1)
from
info
where
userID
like
'%'
||
trim(a.userID)
||
'%')
from
user
a;
以NO字段為主,進(jìn)行分組。
select a.no,sum(a.金額) from table a group by a.no
同一個(gè)NO,會(huì)對(duì)應(yīng)不同的姓名。
select a.no,a.姓名,sum(a.金額) from table a group by a.no,a.姓名
看不懂
目標(biāo)語(yǔ)句:當(dāng)收費(fèi)醒目包含‘鹽’這一項(xiàng),則統(tǒng)計(jì)no='10' 且 姓名=‘張三’,所有收費(fèi)項(xiàng)目對(duì)...
select a.項(xiàng)目,sum(a.金額) from table a where a.收費(fèi)項(xiàng)目= '1' and a.no = '10' and a.姓名=‘張三’ group by a.項(xiàng)目
網(wǎng)站名稱:oracle如何分組統(tǒng)計(jì),oracle分組統(tǒng)計(jì),再求和
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