首先你已經(jīng)很清楚的說明了你這個(gè)程序是用C語(yǔ)言寫二次函數(shù)的,而當(dāng)a=0時(shí),就不是二次函數(shù)了,應(yīng)該按照一次函數(shù)來進(jìn)行計(jì)算,否則 一個(gè)數(shù)除以0就沒有意義了.~

成都創(chuàng)新互聯(lián)是專業(yè)的安澤網(wǎng)站建設(shè)公司,安澤接單;提供成都做網(wǎng)站、成都網(wǎng)站設(shè)計(jì),網(wǎng)頁(yè)設(shè)計(jì),網(wǎng)站設(shè)計(jì),建網(wǎng)站,PHP網(wǎng)站建設(shè)等專業(yè)做網(wǎng)站服務(wù);采用PHP框架,可快速的進(jìn)行安澤網(wǎng)站開發(fā)網(wǎng)頁(yè)制作和功能擴(kuò)展;專業(yè)做搜索引擎喜愛的網(wǎng)站,專業(yè)的做網(wǎng)站團(tuán)隊(duì),希望更多企業(yè)前來合作!
#include stdio.h
#include stdlib.h
#include math.h
int main()
{
float a,b,c;
float x1,x2,m;
printf("input number a=:");
scanf("%f",a);
printf("input number b=:");
scanf("%f",b);
printf("input number c=:");
scanf("%f",c);
if(a==0)
printf("一根:%f\n",c*(-1)/b);
else if(a==0b==0)
printf("無意義!");
else
{
m=b*b-4*a*c;
if(m0)
{
printf("兩根\n");
printf("x1=%f\n",(-b+sqrt(m))/(2*a));
printf("x2=%f\n",(-b-sqrt(m))/(2*a));
}
else if(m==0)
printf("x1=x2=%f\n",x1);
}
else
printf("無實(shí)根\n");
}
return 0;
}
#include stdio.h
#include stdlib.h
#include math.h
int main()
{
float a,b,c;
float x1,x2,m;
printf("input number a=:");
scanf("%f",a);
printf("input number b=:");
scanf("%f",b);
printf("input number c=:");
scanf("%f",c);
m=b*b-4*a*c;
if(m=0a!=0){
if(m0){
x1=(-b+sqrt(m))/(2*a);
x2=(-b-sqrt(m))/(2*a);
printf("兩根\n");
printf("x1=%f\n",x1);
printf("x2=%f\n",x2);}
else
printf("一根\n");
printf("x1=x2=%f\n",x1);}
else
{
if(a=0 b!=0) printf("根是x=-c/b");
if(a=0b=0) printf("為常函數(shù)");
if(a!=0) printf("無根\n");
}
system("PAUSE");
return 0; }
這個(gè)簡(jiǎn)單啊
#includestdio.h
#includemath.h
main()
{
double a,b,c,w;
printf("請(qǐng)輸入三個(gè)數(shù)(方程的系數(shù)),中間用空格分開\n");
scanf("%lf%lf%lf",a,b,c);
w=b*b-4*a*c;
if (w0)printf("方程無解\n");
else if(w==0)printf("方程有一個(gè)解:x=%lf\n",-b/(2*a));
else printf("方程有兩個(gè)解:x1=%lf,x2=%lf\n",(-b+sqrt(w))/(2*a),(-b-sqrt(w))/(2*a));
}
#include?windows.h
LRESULT?CALLBACK?WndProc(HWND,?UINT,?WPARAM,?LPARAM);
int?WINAPI?WinMain(HINSTANCE?hInstance,?HINSTANCE?hPrevInstance,
PSTR?szCmdLine,?int?iCmdShow)
{
static?TCHAR?szAppName[]=TEXT("二次函數(shù)");
HWND?????????hwnd;
MSG??????????msg;
WNDCLASS?????wndclass;
wndclass.style=CS_HREDRAW|CS_VREDRAW;
wndclass.lpfnWndProc=WndProc;
wndclass.cbClsExtra=0;
wndclass.cbWndExtra=0;
wndclass.hInstance=hInstance;
wndclass.hIcon=LoadIcon(NULL,?IDI_APPLICATION);
wndclass.hCursor=LoadCursor(NULL,?IDC_ARROW);
wndclass.hbrBackground=(HBRUSH)GetStockObject(WHITE_BRUSH);
wndclass.lpszMenuName=NULL;
wndclass.lpszClassName=szAppName;
if?(!RegisterClass(wndclass))
{
MessageBox(NULL,?TEXT("Error"),
szAppName,?MB_ICONERROR);
return?0;
}
hwnd=CreateWindow(szAppName,?TEXT("二次函數(shù)"),
WS_OVERLAPPEDWINDOW,
CW_USEDEFAULT,?CW_USEDEFAULT,
CW_USEDEFAULT,?CW_USEDEFAULT,
NULL,?NULL,?hInstance,?NULL);
ShowWindow(hwnd,?iCmdShow);
UpdateWindow(hwnd);
while?(GetMessage(msg,?NULL,?0,?0))
{
TranslateMessage(msg);
DispatchMessage(msg);
}
return?msg.wParam;
}
LRESULT?CALLBACK?WndProc(HWND?hwnd,?UINT?message,?WPARAM?wParam,?LPARAM?lParam)
{
static?int??cxClient,?cyClient;
const?static?int?n=1000;
HDC?????????hdc;
int?????????i;
PAINTSTRUCT?ps;
POINT???????apt[n];
switch?(message)
{
case?WM_SIZE:
cxClient=LOWORD(lParam);
cyClient=HIWORD(lParam);
return?0;
case?WM_PAINT:
hdc=BeginPaint(hwnd,?ps);
MoveToEx(hdc,?0,?cyClient/2,?NULL);
LineTo(hdc,?cxClient,?cyClient/2);
MoveToEx(hdc,?cxClient/2,?0,?NULL);
LineTo(hdc,?cxClient/2,?cyClient);
for?(i=0;?i??n;++i)
{
apt[i].x=cxClient/4+i; apt[i].y=cyClient-(cyClient/2-i)*(cyClient/2-i)/300-cyClient/2+100;
}
Polyline(hdc,?apt,?n);
return?0;
case?WM_DESTROY:
PostQuitMessage(0);
return?0;
}
return?DefWindowProc(hwnd,?message,?wParam,?lParam);
}
文章題目:c語(yǔ)言如何實(shí)現(xiàn)二次函數(shù),c語(yǔ)言如何調(diào)用兩次函數(shù)
文章轉(zhuǎn)載:http://chinadenli.net/article26/hedsjg.html
成都網(wǎng)站建設(shè)公司_創(chuàng)新互聯(lián),為您提供關(guān)鍵詞優(yōu)化、定制網(wǎng)站、軟件開發(fā)、搜索引擎優(yōu)化、網(wǎng)站建設(shè)、外貿(mào)建站
聲明:本網(wǎng)站發(fā)布的內(nèi)容(圖片、視頻和文字)以用戶投稿、用戶轉(zhuǎn)載內(nèi)容為主,如果涉及侵權(quán)請(qǐng)盡快告知,我們將會(huì)在第一時(shí)間刪除。文章觀點(diǎn)不代表本網(wǎng)站立場(chǎng),如需處理請(qǐng)聯(lián)系客服。電話:028-86922220;郵箱:631063699@qq.com。內(nèi)容未經(jīng)允許不得轉(zhuǎn)載,或轉(zhuǎn)載時(shí)需注明來源: 創(chuàng)新互聯(lián)