JS兩個數(shù)組根據(jù)相同的ID進行重新組合數(shù)據(jù)？

var c = a.concat(b),//合并成一個數(shù)組

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temp = {},//用于id判斷重復

result = [];//最后的新數(shù)組

//遍歷c數(shù)組，將每個item.id在temp中是否存在值做判斷，如不存在則對應的item賦值給新數(shù)組，并將temp中item.id對應的key賦值，下次對相同值做判斷時便不會走此分支，達到判斷重復值的目的；

c.map((item,index)={

if(!temp[item.id]){

result.push(item);

temp[item.id] = true

}

})

console.log(result)

js json解析并重組成二維數(shù)組

var?arr?=?[{a:1},{a:2},{a:3},{b:5},{b:7},{b:10}];

var?newArr?=?[];

arr.map(e=Object.keys(e)[0]).filter((e,i,o)=o.indexOf(e)===i).map(e={

arr.filter((e1,i)=Object.keys(e1)==e).forEach((e,i)={

if(!newArr[i])newArr[i]=[];

newArr[i].push(e);

});

});

console.log(newArr);

js獲取json字符串后如何按格式重組？

題目沒有怎么看懂啊

用正則啊

function?rookitReg(){

var?reg?=?/\(\d+,\d+\)/g;

var?str?=?"某某某(02,000002)某某某(02,000005)某某某(02,000101)某某(02,000111)某某某......";

alert(new?RegExp(reg).test(str));

str?=?str.replace(reg,"");?//?替換你要替換的，什么下拉框，單選框啥子哦

}

JS數(shù)組對象中有相同值的數(shù)據(jù)拿出相同的對象重組

const List = [{"end_date":"2022-02-10","end_seconds":1644488295.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-10 18:08:34","id":10319,"last_heart_beat_time":"2022-02-10 18:18:15","scanner_id":167,"start_date":"2022-02-10","start_seconds":1644487714.0,"start_total_seconds":581},{"end_date":"2022-02-11","end_seconds":1644550497.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 11:19:08","id":10338,"last_heart_beat_time":"2022-02-11 11:34:57","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644549548.0,"start_total_seconds":949},{"end_date":"2022-02-11","end_seconds":1644558220.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 11:48:41","id":10339,"last_heart_beat_time":"2022-02-11 13:43:40","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644551321.0,"start_total_seconds":6899},{"end_date":"2022-02-11","end_seconds":1644558820.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 13:53:40","id":10343,"last_heart_beat_time":"2022-02-11 13:53:40","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644558820.0,"start_total_seconds":0},{"end_date":"2022-02-11","end_seconds":1644563620.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 14:03:41","id":10344,"last_heart_beat_time":"2022-02-11 15:13:40","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644559421.0,"start_total_seconds":4199},{"end_date":"2022-02-11","end_seconds":1644586551.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 15:55:51","id":10350,"last_heart_beat_time":"2022-02-11 21:35:51","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644566151.0,"start_total_seconds":20400},{"end_date":"2022-02-13","end_seconds":1644759468.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-13 14:47:48","id":10410,"last_heart_beat_time":"2022-02-13 21:37:48","scanner_id":167,"start_date":"2022-02-13","start_seconds":1644734868.0,"start_total_seconds":24600},{"end_date":"2022-02-14","end_seconds":1644846304.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-14 10:15:05","id":10430,"last_heart_beat_time":"2022-02-14 21:45:04","scanner_id":167,"start_date":"2022-02-14","start_seconds":1644804905.0,"start_total_seconds":41399},{"end_date":"2022-02-15","end_seconds":1644911999.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-15 15:30:00","id":10468,"last_heart_beat_time":"2022-02-15 15:59:59","scanner_id":167,"start_date":"2022-02-15","start_seconds":1644910200.0,"start_total_seconds":1799},{"end_date":"2022-02-15","end_seconds":1644932084.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-15 19:44:44","id":10472,"last_heart_beat_time":"2022-02-15 21:34:44","scanner_id":167,"start_date":"2022-02-15","start_seconds":1644925484.0,"start_total_seconds":6600},{"end_date":"2022-02-16","end_seconds":1645020217.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-16 15:13:37","id":10491,"last_heart_beat_time":"2022-02-16 22:03:37","scanner_id":167,"start_date":"2022-02-16","start_seconds":1644995617.0,"start_total_seconds":24600},{"end_date":"2022-02-17","end_seconds":1645089245.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-17 14:59:06","id":10521,"last_heart_beat_time":"2022-02-17 17:14:05","scanner_id":167,"start_date":"2022-02-17","start_seconds":1645081146.0,"start_total_seconds":8099}]

? ? const newArray = []

? ? List.forEach(item = {

? ? ? ? // 第一次循環(huán),repeat定義repet,基于find淺拷貝特性,操作repeat會影響到newArray

? ? ? ? // 循環(huán)開始,find的條件不成立,就會push一個新對象{data: item.start_date,times: [item]}進去

? ? ? ? // 檢索條件要注意,find的核對條件需要準確

? ? ? ? // 第二次循環(huán),find條件成立,則走else

? ? ? ? const repeat = newArray.find(res = res.data === item.start_date)

? ? ? ? if (!repeat) {

? ? ? ? ? ? newArray.push({

? ? ? ? ? ? ? ? data: item.start_date,

? ? ? ? ? ? ? ? times: [item]

? ? ? ? ? ? })

? ? ? ? } else {

? ? ? ? ? ? // 避免循環(huán)紊亂,不用item.times.push(item),選用repeat.times.push(item)

? ? ? ? ? ? repeat.times.push(item)

? ? ? ? }

? ? })

打印數(shù)據(jù)后可以看到，已經(jīng)將數(shù)據(jù)成功照相同時間的start_date重新管理

如果前端需要解決時間歸類當天的用戶多部操作但是后端沒處理，就可以用forEach+find的方法處理

JS json數(shù)據(jù)重組如何把后面json的轉(zhuǎn)換成前面的json啊?

var?jsonA=[];

JSONB.forEach(function(o){

if(o.title){

var?oo={title:o.title,item:[]};

JSONB.forEach(function(o){

if(o.title==oo.title){

oo.item.push(o.item);

o.title="";

}

})

jsonA.push(oo);

}

})

console.log(jsonA);

用javascript 將對象按屬性名稱排序重組

//定義一個對象數(shù)組

　var data = [{ name: "jiang", age: 22 }, { name: "AAAAAAAAAAAAAA", age: 21 }, { name: "CCCCCCCCc", age: 25}];

　//定義一個比較器

function compare(propertyName) {

return function (object1, object2) {

var value1 = object1[propertyName];

var value2 = object2[propertyName];

if (value2 value1) {

return -1;

}

else if (value2 value1) {

return 1;

}

else {

return 0;

}

}

}

//使用方法

data.sort(compare("name"));

alert(data[0].name);//jiang

//使用方法

data.sort(compare("age"));

alert(data[0].age);//25s

當前名稱：javascript重組,js重組數(shù)組
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