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php怎么取出10條數(shù)據(jù),mysql取10條數(shù)據(jù)

php yii 怎么隨機(jī)從數(shù)據(jù)庫里獲取10條數(shù)據(jù)

mysql:SELECT * FROM table order by rand() limit 10;

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從數(shù)據(jù)庫隨機(jī)取出來之后再用php處理一下,按照你的需求再排序咯。然后樓主還有什么疑問的話,還不懂,可以去后盾人看看,里面有些資料,興許能夠幫助你

php mysql 只取10個數(shù)據(jù)

$sql = "SELECT * FROM chat WHERE id ".$lastID." ORDER BY id ASC LIMIT 60";

改為

$sql = "SELECT * FROM chat WHERE id ".$lastID." ORDER BY id ASC LIMIT 0,10";

php 循環(huán)二維數(shù)組取十條數(shù)據(jù)

你給出的數(shù)據(jù)組織形式,貌似是json,那么你可以直接用json_encode() 和 json_decode()進(jìn)行轉(zhuǎn)換后,再進(jìn)行處理。

示例代碼:

?php

$json = '{

"6846": {

"userid": "6846",

"expertname": "三劍客",

"firstrate": "0",

"wrong": null,

"firstqs": "2011254",

"firstvalue": "2",

"lastrate": "0",

"firstnum": "0",

"lastnum": "0",

"kjtime": "2012-09-30 00:00:00",

"successrate": "0",

"curqs": " (2012267,2012266,2012262,2012259,2011256,2011255,2011254 )",

"lastpaiming": "1",

"curpaiming": "1"

},

"9205": {

"userid": "9205",

"expertname": "東方諸葛",

"firstrate": "0",

"wrong": null,

"firstqs": "2011254",

"firstvalue": "2",

"lastrate": "0",

"firstnum": "0",

"lastnum": "0",

"kjtime": "2012-09-30 00:00:00",

"successrate": "0",

"curqs": " (2012267,2012266,2012262,2012259,2011256,2011255,2011254 )",

"lastpaiming": "2",

"curpaiming": "2"

},

"9213": {

"userid": "9213",

"expertname": "神探老李",

"firstrate": "0",

"wrong": null,

"firstqs": "2011254",

"firstvalue": "2",

"lastrate": "0",

"firstnum": "0",

"lastnum": "0",

"kjtime": "2012-09-30 00:00:00",

"successrate": "0",

"curqs": " (2012267,2012266,2012262,2012259,2011256,2011255,2011254 )",

"lastpaiming": "3",

"curpaiming": "3"

},

"17518": {

"userid": "17518",

"expertname": "草原雄鷹",

"firstrate": "0",

"wrong": null,

"firstqs": "2011254",

"firstvalue": "2",

"lastrate": "0",

"firstnum": "0",

"lastnum": "0",

"kjtime": "2012-09-30 00:00:00",

"successrate": "0",

"curqs": " (2012267,2012266,2012262,2012259,2011256,2011255,2011254 )",

"lastpaiming": "4",

"curpaiming": "4"

}

}';

echo 'Pre';

print_r( json_decode($json,true) );

echo '/pre';

?

PHP中如何取數(shù)據(jù)庫某一字段的某一狀態(tài)在的后10條數(shù)據(jù)

先找出狀態(tài)=1的最大cid:X,然后搜索cid = X的那一行:

select name from 表名 where cid = (select max(cid) from 表名 where status=1) 其中status類型要為int

如果是varchar,就要寫成status='1'

php怎么把從數(shù)據(jù)庫里查詢的數(shù)據(jù)十條一頁的顯示出來

按照樓主已死貼出完整代碼,看不懂再問

$sql="select * from `user` order by `id` desc";//自己隨便寫一個sql語句測試用,根據(jù)自己需求替換,不要加limit

$pagesize=10;

$num=mysql_num_rows(mysql_query($sql));

$pagecount=ceil($num/$pagesize);

$pageall=$num;

if(!isset($_GET["page"])){//這里翻頁模式用GET方式傳參解決,?page=1的方式

$pageindex="1";

}else{

$pageindex=$_GET["page"];

if($pageindex==""){

$pageindex="1";

}elseif(!is_numeric($pageindex)){

$pageindex="1";

}elseif(substr_count($pageindex,".")!=0){

$pageindex="1";

}elseif($pageindex$pagecount){

$pageindex=$pagecount;

}elseif($pageindex=1){

$pageindex="1";

}

}

if($pageindex$pagecount){

$start=($pageindex-1)*$pagesize;

$sql1=$sql." limit ".$start.",".$pagesize;

}else{

if($num%$pagesize!=0){

$start=($pageindex-1)*$pagesize;

$sql1=$sql." limit ".$start.",".($num%$pagesize);

}else{

$start=($pageindex-1)*$pagesize;

$sql1=$sql." limit ".$start.",".$pagesize;

}

}

$result=mysql_query($sql1);

while($RS = @mysql_fetch_array($result)){

//按要求讀出每次循環(huán)的字段

}

php如何重復(fù)調(diào)用輸出數(shù)據(jù)?比如說10條。

明白你的意思了。

$a = mysql_query("select * from table_name", $link); //這個地方你的寫法有問題,兩個參數(shù)外不需要加引號,我的是正確的

這個$a只是mysql一個資源集,你要用mysql_fetch_array這個函數(shù)循環(huán)從里面提取數(shù)據(jù),具體可以查手冊mysql_fetch_array的用法,完整代碼是:

$a = mysql_query("select * from table_name", $link);

while ( $row = mysql_fetch_array($a) )

{

print_r($row); //$row 就是一行數(shù)據(jù),是一個數(shù)組

}

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